(DA) Feb 24, 2011: Solution Chemistry

Example

• 100mL of 0.250 M Iron (II) Chloride reacts with excess copper. How many grams of Iron are produced?
  
  FeCl2 + Cu -> CuCl2 + Fe
  
  0.100L x 0.250 mol x 1 x 55.8g = 1.40 g
                        L          1     1mol
  

• How many moles of Copper (II) Chloride are produced?
  
  0.100 L x 0.250 mol x 1 = 0.0250 mol
                         L          1
  
• Determine [CuCl2]
  
  0.0250 mol x 1 = 0.250 mol/L
                    0.100L